C4627 ошибка c

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  • Question

  • Good day

    Newbie

    Error on precompiled header.

    \\ program

    #include <iostream.h>

    main()
    {
    cout << «Hello Kitty!»;
    return 0;
    }

    Returns : WARNING C4627. #include <iostream.h>`: skipped when looking for precompiled header.

    no matter what header I use I get the same warning.

    #include <stdio.h> = error

    #include <stdafx.h> = error

    #include <iostream> = error 

    Tried to reinstall on the C disk. And tools> import and export setting>reset all setting.

    still errors

    what does it mean ?

    • Edited by

      Monday, February 16, 2015 8:30 PM

    • Moved by
      Barry Wang
      Tuesday, February 17, 2015 8:24 AM

Answers

  • The default is to enable pre-compiled headers. If this case you aren’t using a precompiled header, so just turn this option off.

    Right-click on the project, Properties, Configuration Properties, C/C++, Precompiled Headers, now change the Precompiled Header option to «Not Using Precompiled Headers»

    • Proposed as answer by
      Shu 2017
      Tuesday, February 17, 2015 8:24 AM
    • Marked as answer by
      Shu 2017
      Tuesday, February 24, 2015 10:13 AM

Шустрый
*

Профиль
Группа: Участник
Сообщений: 62
Регистрация: 6.4.2009

Репутация: нет
Всего: нет

Доброго дня суток!
Попробовал я написать проект (из учебника), который состоит из двух файлов (VS2013):

Код

// File 1.cpp: определяет точку входа для консольного приложения.
//
#include <iostream>
#include "stdafx.h"
using namespace std;

// Внешняя переменная 
double warming = 0.3;
// Прототипы функций 
void update(double dt);
void local();

int _tmain(int argc, _TCHAR* argv[])
{
    cout << "Global warming is " << warming << " degrees. \n";
    update(0.1); // вызов функции, изменяющей warming 
    cout << "Global warming is " << warming << " degrees. \n";
    local(); // вызов функции с локальной переменной warming 
    cout << "Global warming is " << warming << " degrees. \n";
        return 0;

}

Код

//support.cpp
#include <iostream>
#include "stdafx.h"
extern double warming;

void update(double dt);
void local();

using namespace std;

void update(double dt)
{
    extern double warming;
    warming += dt;
    cout << "Updating global warming to " << warming << "degrees.\n";
}
void local()
{
    double warming = 0.8;
    cout << "Local warming = " << warming << "degrees.\n" << "But global warming = " << ::warming << "degrees.\n";

Да вот беда, компилятор ругается: warning C4627: #include <iostream>: пропущен при поиске использования предкомпилированного заголовка
1>          Добавление директивы в «stdafx.h» или перестройка предкомпилированного заголовка

и, конечно, исходящие из этого ошибки:  error C2065: cout: необъявленный идентификатор

Как это понимать и как вылечить?

Это сообщение отредактировал(а) Ukrajinec — 2.1.2015, 21:57

If the «Use precompiled header file» option is set, the compiler will disregard all content in the file prior to including the precompiled header. Visual Studio 2015 and earlier versions will produce a warning (C4627) if the «header_file» is included before the precompiled header file, but the precompiled header file does not include «header_file» as well.

Table of contents

  • Compiler Warning (level 1) C4627
  • Warning C4627 error on precompiled header
  • Why I am getting this error in c++ code
  • C4503 warnings? How do i solve/get rid of them?
  • What is error c4627 in Visual Studio?
  • What’s the difference between c4603 and c4627?
  • How to suppress the error c4427 and c4438?
  • How do I suppress the c4096 error message?

Compiler Warning (level 1) C4627

The header file, labeled as »
skipped when looking for precompiled header
«, is used.

If the /Yu (Use
precompiled header
file) option is enabled in the current source file, the compiler disregards any content in the file until the precompiled header is included. A warning, C4627, is produced in
visual studio
2015 and earlier versions if the header_file is included before the
precompiled header file
and if the precompiled header does not include the header_file as well.

Example

This example illustrates the occurrence of the error and provides a solution for it.

// c4627.cpp
#include        // C4627 - iostream not included by pch.h
#include "pch.h"          // precompiled header file that does not include iostream
// #include     // To fix, move the iostream header include here from above
int main()
{
    std::cout << "std::cout is defined!\n";
}

Creating Precompiled Header Files

VS2015 Compile-time error when I write an header and a, If your project is configured to use precompiled headers (default), you need to include the stdafx.h file as the first #include from each .cpp file in the project.


Question:

Good day

Newbie

Error on precompiled header.

\\ program

#include

main()

{



cout << «Hello Kitty!»;



return 0;

}

The function returns a warning C4627 due to the inclusion of the header #include <iostream.h> in the code.

Regardless of the header I utilize, I receive the identical warning.

#include <stdio.h> = error

#include <
stdafx.h
> = error

#include <iostream> = error

I attempted to reinstall on the C disk and then reset all settings through tools > import and export settings.

still errors

what does it mean ?


Solution:

By default, pre-compiled headers are enabled. However, if you are not using a precompiled header, you can simply disable this option.

To modify the Precompiled Header option to «Not Using Precompiled Headers», follow these steps: right-click on the project, go to Properties, then Configuration Properties, C/C++, and finally Precompiled Headers.

Warning C4627 error on precompiled header, Windows Server Developer Center. Sign in. United States (English)

Why I am getting this error in c++ code


Question:

I have this simple code:

std::ifstream ifs;
ifs.open ("test.txt", std::ifstream::in);
char c = ifs.get();
while (ifs.good()) {
   std::cout << c;
   c = ifs.get();
}
ifs.close();

However, I am encountering numerous errors, including:

Error   9   error C3083: 'ifstream': the symbol to the left of a '::' must be a type    test.cpp    
Error   8   error C2228: left of '.open' must have class/struct/union   test.cpp

and so on.

At the beginning of the file, I have included these definitions.

#include 
#include 
#include "stdafx.h"
using namespace std;

I am utilizing VS2012 for a console application.

edit1:

The complete code is as follow:

void ReadRawImages::Read(int frameNumber)
{
std::ifstream ifs;
      ifs.open ("test.txt", std::ifstream::in);
       char c = ifs.get();
       while (ifs.good()) {
            std::cout << c;
            c = ifs.get();
       }
  ifs.close();
 }

Additionally, I observed the presence of these warnings.

Warning 1   warning C4627: '#include ': skipped when looking for precompiled header use   test.cpp
Warning 2   warning C4627: '#include ': skipped when looking for precompiled header use    test.cpp


Solution 1:

Place the header files following the

#include "stdafx.h"

declaration.

#include "stdafx.h"
#include 
#include 

The first included file, as per Microsoft’s specific rule, should always be

stdafx.h

.

By default, Visual C++ will only compile the code after the «#
include «stdafx.h
» in the source file if the compile option /Yu’stdafx.h’ is checked.


Solution 2:

If your project is utilizing precompiled headers, ensure that the initial line of each

.cpp

file follows this format.

#include "stdafx.h"

Whatever the name of the header may be, or any other alternative name.

Compiler Warning (level 1) C4624, Compiler Warning (level 1) C4624. ‘derived class’ : destructor was implicitly defined as deleted because a base class destructor is inaccessible or …

C4503 warnings? How do i solve/get rid of them?


Question:

I am new to C++ STL and currently experimenting with it. My objective is to create a map-based multidimensional associative array.

typedef struct DA {
    string  read_mode;
    string  data_type;
    void    *pValue;
    void    *pVarMemLoc;
}DA;
int main()
{
    map>>>> DATA;
    DATA["lvl1"]["stg1"]["flr1"]["dep1"]["rom1"] = new DA;
    DATA["lvl1"]["stg1"]["flr1"]["dep1"]["rom2"] = new DA;
    DATA["lvl1"]["stg1"]["flr1"]["dep1"]["rom3"] = new DA;
    IEC["lvl1"]["stg1"]["flr1"]["dep1"]["rom1"]->read_mode = "file";
    IEC["lvl1"]["stg1"]["flr1"]["dep1"]["rom2"]->read_mode = "poll";
    IEC["lvl1"]["stg1"]["flr1"]["dep1"]["rom3"]->read_mode = "report";
    return 0;
}

Upon compiling the aforementioned code in VS2005, I encountered 170 C4503 warnings, all of which pertain to the «decorated name length exceeded, name was truncated» issue. Despite these warnings, the program appears to execute without any issues.

Would anyone be willing to provide me with an explanation of the reasons behind these warnings and share a solution? I appreciate your assistance in advance.

Warning 1   warning C4503: 'std::map<_Kty,_Ty>::~map' : decorated name length exceeded, name was truncated  c:\program files\microsoft visual studio 8\vc\atlmfc\include\cstringt.h 2121
Warning 2   warning C4503: 'std::map<_Kty,_Ty>::map' : decorated name length exceeded, name was truncated   c:\program files\microsoft visual studio 8\vc\atlmfc\include\cstringt.h 2121
Warning 3   warning C4503: 'std::map<_Kty,_Ty>::operator []' : decorated name length exceeded, name was truncated   c:\program files\microsoft visual studio 8\vc\atlmfc\include\cstringt.h 2121
Warning 4   warning C4503: 'std::_Tree<_Traits>::~_Tree' : decorated name length exceeded, name was truncated   c:\program files\microsoft visual studio 8\vc\atlmfc\include\cstringt.h 2121
Warning 5   warning C4503: 'std::map<_Kty,_Ty>::operator []' : decorated name length exceeded, name was truncated   c:\program files\microsoft visual studio 8\vc\atlmfc\include\cstringt.h 2121
Warning 6   warning C4503: 'std::_Tree<_Traits>::iterator::~iterator' : decorated name length exceeded, name was truncated  c:\program files\microsoft visual studio 8\vc\atlmfc\include\cstringt.h 2121
Warning 7   warning C4503: 'std::_Tree<_Traits>::iterator::iterator' : decorated name length exceeded, name was truncated   c:\program files\microsoft visual studio 8\vc\atlmfc\include\cstringt.h 2121


Solution 1:

As per my research, I don’t support the idea of disabling the warning since it may lead to unintended consequences; therefore, I prefer to completely address the issue.

This is my approach to rewriting the code.

typedef struct DA {
    string  read_mode;
    string  data_type;
    void    *pValue;
    void    *pVarMemLoc;
}DA;
struct ROOM{
    map map;
};
struct DEPARTMENT{
    map map;
};
struct FLOOR{
    map map;
};
struct STAGE{
    map map;
};   
struct LEVEL{
    map map;
};   

and you could use it like this:

int main()
{
    LEVEL DATA;
    DATA.map["lvl1"].map["stg1"].map["flr1"].map["dep1"].map["rom1"] = new DA;
    DATA.map["lvl1"].map["stg1"].map["flr1"].map["dep1"].map["rom2"] = new DA;
    DATA.map["lvl1"].map["stg1"].map["flr1"].map["dep1"].map["rom3"] = new DA;
    ...
    etc

The source of my concerns and the eventual solution mainly come from MSDN.
«»».


Solution 2:

If you have plans to retain this colossal
data structure
, there are limited options available to address the warning, except disabling it.

#pragma warning(disable:4503)


Solution 3:

While some have proposed methods to disable the warning, I recommend reconsidering your design approach. Incorporate additional layers of abstraction beyond map^5, or modify the storage data structure. For instance, consider using map in place of map^5.


Updated:

Essentially, you have two choices in this scenario.

  • You can utilize a key with an adjustable number of strings/levels as per your requirements.

    <p>
    <code>
    struct Key3 { std::string x, y, z; };
    </code>
    <code>
    typedef std::map&lt;Key3, DA*&gt; MyMap;
    </code>
    </p>

  • Alternatively, you can create a generic structure in which each level has the ability to store either the DA* value or another level.


Solution 4:

Announce in a manner that warrants attention, taking care to close the quotation marks.

map > > > > DATA;

The shift operator in C++ is recognized as

>>

.

Compiler Warning (level 4) C4127, In this article. conditional expression is constant. Remarks. The controlling expression of an if statement or while loop evaluates to a constant. …

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