When I run this code then following error is encountered, I am new to programming and I know I have bunch of useless arrays. I don’t know where my error is as I have declared j as an array. I am completely out of ideas.
import pyodbc,nltk,array,re,itertools
cnxn = pyodbc.connect('Driver={MySQL ODBC 5.1 Driver};Server=127.0.0.1;Port=3306;Database=information_schema;User=root; Password=1234;Option=3;')
cursor = cnxn.cursor()
cursor.execute("use collegedatabase ;")
cursor.execute("select * from sampledata ; ")
cnxn.commit()
s=[]
j=[]
x=[]
words = []
w = []
sfq = []
POS=[]
wnl = nltk.WordNetLemmatizer()
p = []
clean= []
l =[]
tupletolist= []
results = []
aux = []
regex = re.compile("\w+\.")
pp = []
array1=[]
f = open("C:\\Users\\vchauhan\\Desktop\\tupletolist.txt","w")
for entry in cursor:
s.append(entry.injury_type),j.append(entry.injury_desc)
def isAcceptableChar(character):
return character not in "~!@#$%^&*()_+`1234567890-={}|:<>?[]\;',/."
from nltk.tokenize import word_tokenize
from nltk.corpus import stopwords
english_stops = set(stopwords.words('english'))
for i in range(0,200):
j.append(filter(isAcceptableChar, j[i]))
w.append([word for word in word_tokenize(j[i].lower()) if word not in english_stops])
for j in range (0,len(w[i])):
results = regex.search(w[i][j])
if results:
str.rstrip(w[i][j],'.')
for a in range(0 , 200):
sfq.append(" ".join(w[a]))
from nltk.stem import LancasterStemmer
stemmer = LancasterStemmer()
for i in range (0,200):
pp.append(len(w[i]))
for a in range (0,200):
p.append(word_tokenize(sfq[a]))
POS.append([wnl.lemmatize(t) for t in p[a]])
x.append(nltk.pos_tag(POS[a]))
clean.append((re.sub('()[\]{}'':/\-[(",)]','',str(x[a]))))
cursor.execute("update sampledata SET POS = ? where SRNO = ?", (re.sub('()[\]{}'':/\-[(",)]','',str(x[a]))), a)
for i in range (0,len(array1)):
results.append(regex.search(array1[i][0]))
if results[i] is not None:
aux.append(i)
f.write(str(w))
Exception:
Traceback (most recent call last):
File "C:\Users\vchauhan\Desktop\regexsolution_try.py", line 37, in <module>
j.append(filter(isAcceptableChar, j[i]))
AttributeError: 'int' object has no attribute 'append'
There are many inbuilt functions in the Python programming language for the data structure. The function append() is one of them. It allows you to add elements at the end of the list. But while implementing this method, make sure to use it correctly otherwise you can get AttributeError: ‘int’ object has no attribute ‘append’ error.
In this entire tutorial, you will know why this error comes and how to solve it.
The main cause of the ‘int’ object has no attribute ‘append’ is that you are appending new elements in the integer part. Let’s say I have a list of integers. If I will try to add a new integer to the selected element from the list, then I will get the error.
sample_list = [10,20,30,40,50]
sample_list[1].append(60)Output
The other case when you will get the error is applying append() method to the integer variable by mistake. For example, I have a variable of integer type. If I append another integer to this integer variable then I will get the ‘int’ object has no attribute ‘append’ error.
value = 10
value.append(20)Output
Solution of AttributeError: ‘int’ object has no attribute ‘append’
The solution to this attributeError is very simple. Look at the causes of this error. The error was mostly due to appending elements or using the append() method on the variable of integer type.
So to not get this AttributeError you have to use the append() method on the list type variable only.
Now if you run the below lines of code then you will not get the AttributeError: ‘int’ object has no attribute ‘append’.
sample_list = [10,20,30,40,50]
sample_list.append(60)
print(sample_list)Output
Conclusion
Sometimes you have to carefully use the python inbuilt function. You should be aware that what is the type of the variable is accepted by any method. The above solution work best for the AttributeError: ‘int’ object has no attribute ‘append’ error.
I hope you have liked this tutorial. If you have any queries then you can contact us for more help. Here are some similar errors.
1.Attributeerror: dict object has no attribute append ( Solved )
2.AttributeError: str object has no attribute append (Solved )
What is AttributeError in Python ? Complete Overview
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When I run this code then following error is encountered, I am new to programming and I know I have bunch of useless arrays. I don’t know where my error is as I have declared j as an array. I am completely out of ideas.
import pyodbc,nltk,array,re,itertools
cnxn = pyodbc.connect('Driver={MySQL ODBC 5.1 Driver};Server=127.0.0.1;Port=3306;Database=information_schema;User=root; Password=1234;Option=3;')
cursor = cnxn.cursor()
cursor.execute("use collegedatabase ;")
cursor.execute("select * from sampledata ; ")
cnxn.commit()
s=[]
j=[]
x=[]
words = []
w = []
sfq = []
POS=[]
wnl = nltk.WordNetLemmatizer()
p = []
clean= []
l =[]
tupletolist= []
results = []
aux = []
regex = re.compile("\w+\.")
pp = []
array1=[]
f = open("C:\\Users\\vchauhan\\Desktop\\tupletolist.txt","w")
for entry in cursor:
s.append(entry.injury_type),j.append(entry.injury_desc)
def isAcceptableChar(character):
return character not in "~!@#$%^&*()_+`1234567890-={}|:<>?[]\;',/."
from nltk.tokenize import word_tokenize
from nltk.corpus import stopwords
english_stops = set(stopwords.words('english'))
for i in range(0,200):
j.append(filter(isAcceptableChar, j[i]))
w.append([word for word in word_tokenize(j[i].lower()) if word not in english_stops])
for j in range (0,len(w[i])):
results = regex.search(w[i][j])
if results:
str.rstrip(w[i][j],'.')
for a in range(0 , 200):
sfq.append(" ".join(w[a]))
from nltk.stem import LancasterStemmer
stemmer = LancasterStemmer()
for i in range (0,200):
pp.append(len(w[i]))
for a in range (0,200):
p.append(word_tokenize(sfq[a]))
POS.append([wnl.lemmatize(t) for t in p[a]])
x.append(nltk.pos_tag(POS[a]))
clean.append((re.sub('()[\]{}'':/\-[(",)]','',str(x[a]))))
cursor.execute("update sampledata SET POS = ? where SRNO = ?", (re.sub('()[\]{}'':/\-[(",)]','',str(x[a]))), a)
for i in range (0,len(array1)):
results.append(regex.search(array1[i][0]))
if results[i] is not None:
aux.append(i)
f.write(str(w))
Exception:
Traceback (most recent call last):
File "C:\Users\vchauhan\Desktop\regexsolution_try.py", line 37, in <module>
j.append(filter(isAcceptableChar, j[i]))
AttributeError: 'int' object has no attribute 'append'
Are you encountering Attributeerror int object has no attribute append?
Apparently, when we are working on programming, and developing new programs we can’t avoid facing this error.
In this article, we will look for solutions, and provide example programs, as well as their causes.
But before that, we will understand this attribute error first.
The Attributerror: int object has no attribute append error in python occurs when we try to call the append() function on an integer.
Therefore we need to make sure the value we should call is on type list.
Here’s how this error occurs:
my_list = ['IT', 'SOURCE', 'CODE']
# reassign variable to an integer
my_list = 10
print(type(my_list)) # <class 'int'>
# AttributeError: 'int' object has no attribute 'append'
my_list.append('HI')
Output:
The code above explains my_list variable is reassigned to an integer then we call the append() function, which then caused us the error.
How to fix the Attributeerror int object has no attribute append
Here are the solutions to fix the example error of Attributeerror int object has no attribute append.
Example 1: Correct or remove the reassignment
To fix the error in the example code, we should remove the reassignment or correct it. When we use the append() method it will add the item at the end of the list.
my_list = ['IT', 'SOURCE', 'CODE']
my_list.append('HI')
print(my_list)Output:
[‘IT’, ‘SOURCE’, ‘CODE’, ‘HI’]
Example 2: Remove the index accessor and call the append() method on the list
As we call the append method on an integer will cause an Attributeerror int object has no attribute appenderror.
Take a look at this example code below:
list_numbers = [10, 20, 30]
# AttributeError: 'int' object has no attribute 'append'
list_numbers[0].append(40)
print(list_numbers)Therefore we need to make sure when we are calling the append method we are not accessing the list at its specific index.
Output:
The output demonstrates when we access the list of items in stores in list_numbers variable at index, which is 10, and the called the append method the output throws error instead.
To fix the int object has no attribute appenderror in this example, remove the index accessor and call the append() method on the list.
list_numbers = [10, 20, 30]
list_numbers.append(40)
print(list_numbers) # [10, 20, 30, 40]
Result:
[10, 20, 30, 40]
Example 3: Assigning the result of calling a function that returns an integer to a variable.
This time we can also assign the result of calling a function that returns an integer to a variable.
Here is the example code:
def get_list():
return 100
my_list = get_list()
# AttributeError: 'int' object has no attribute 'append'
my_list.append('itsourecode')The code is trying to append the string ‘itsourecode‘ to an integer value returned by the function get_list(). This will result in an AttributeError since integers don’t have the append() method.
To fix this, you need to change the return type of the function to a list and initialize it with the integer value. Here’s the modified code:
def get_list():
return [100]
my_list = get_list()
my_list.append('itsourcecode')
print(my_list) # output: [100, 'itsourcecode']
Output:
[100, 'itsourcecode']
In this code, the function get_list() returns a list with a single integer value of 100. This list can then be appended with the string ‘itsourcecode‘ using the append() method. The output of the updated code will be [100, ‘itsourcecode’].
Causes of Attributeerror int object has no attribute append
As mentioned, AttributeError “int object has no attribute append” occurs when you try to use the append() method on an integer object.
This error happens because integers are not mutable in Python, meaning you can’t modify them once they are created.
Therefore, they don’t have any methods that modify them in-place, such as append() which is used to add an element to the end of a list.
If you want to store multiple values, you need to use a list or another mutable object.
So, if you try to call the append() method on an integer object, Python raises an AttributeError because it doesn’t exist for that data type.
Conclusion
In conclusion, we should be careful in utilizing the Python built-in functions. Particularly, be aware of the type of variable we are using and whether it is acceptable in the method we are using.
Hence the solution we provided above will fix the AttributeError: ‘int’ object has no attribute ‘append’ error. Choose what works best for you.
If you are finding solutions to some errors you might encounter we also have Attributeerror: ‘dict’ object has no attribute ‘read’.
You set a list first, then replace that list with the value:
else:
levels[curr_node.dist] = []
levels[curr_node.dist].append(curr_node.tree_node.val)
levels[curr_node.dist] = curr_node.tree_node.val
Drop that last line, it breaks your code.
Instead of using if...else, you could use the dict.setdefault() method to assign an empty list when the key is missing, and at the same time return the value for the key:
levels.setdefault(curr_node.dist, []).append(curr_node.tree_node.val)
This one line replaces your 6 if: ... else ... lines.
You could also use a collections.defaultdict() object:
from collections import defaultdict
levels = defaultdict(list)
and
levels[curr_node.dist].append(curr_node.tree_node.val)
For missing keys a list object is automatically added. This has a downside: later code with a bug in it that accidentally uses a non-existing key will get you an empty list, making matters confusing when debugging that error.