(PHP 4, PHP 5)
mysql_error — Возвращает текст ошибки последней операции с MySQL
Описание
mysql_error(resource $link_identifier = NULL): string
Список параметров
-
link_identifier -
Соединение MySQL. Если идентификатор соединения не был указан,
используется последнее соединение, открытое mysql_connect(). Если такое соединение не было найдено,
функция попытается создать таковое, как если бы mysql_connect() была вызвана без параметров.
Если соединение не было найдено и не смогло быть создано, генерируется ошибка уровняE_WARNING.
Возвращаемые значения
Возвращает текст ошибки выполнения последней функции MySQL,
или '' (пустую строку), если операция
выполнена успешно.
Примеры
Пример #1 Пример использования mysql_error()
<?php
$link = mysql_connect("localhost", "mysql_user", "mysql_password");mysql_select_db("nonexistentdb", $link);
echo mysql_errno($link) . ": " . mysql_error($link). "\n";mysql_select_db("kossu", $link);
mysql_query("SELECT * FROM nonexistenttable", $link);
echo mysql_errno($link) . ": " . mysql_error($link) . "\n";
?>
Результатом выполнения данного примера
будет что-то подобное:
1049: Unknown database 'nonexistentdb' 1146: Table 'kossu.nonexistenttable' doesn't exist
aleczapka _at) gmx dot net ¶
19 years ago
If you want to display errors like "Access denied...", when mysql_error() returns "" and mysql_errno() returns 0, use $php_errormsg. This Warning will be stored there. You need to have track_errors set to true in your php.ini.
Note. There is a bug in either documentation about error_reporting() or in mysql_error() function cause manual for mysql_error(), says: "Errors coming back from the MySQL database backend no longer issue warnings." Which is not true.
Pendragon Castle ¶
14 years ago
Using a manipulation of josh ><>'s function, I created the following. It's purpose is to use the DB to store errors. It handles both original query, as well as the error log. Included Larry Ullman's escape_data() as well since I use it in q().
<?php
function escape_data($data){
global $dbc;
if(ini_get('magic_quotes_gpc')){
$data=stripslashes($data);
}
return mysql_real_escape_string(trim($data),$dbc);
}
function
q($page,$query){
// $page
$result = mysql_query($query);
if (mysql_errno()) {
$error = "MySQL error ".mysql_errno().": ".mysql_error()."\n<br>When executing:<br>\n$query\n<br>";
$log = mysql_query("INSERT INTO db_errors (error_page,error_text) VALUES ('$page','".escape_data($error)."')");
}
}
// Run the query using q()
$query = "INSERT INTO names (first, last) VALUES ('myfirst', 'mylast'");
$result = q("Sample Page Title",$query);
?>
Florian Sidler ¶
13 years ago
Be aware that if you are using multiple MySQL connections you MUST support the link identifier to the mysql_error() function. Otherwise your error message will be blank.
Just spent a good 30 minutes trying to figure out why i didn't see my SQL errors.
l dot poot at twing dot nl ¶
17 years ago
When creating large applications it's quite handy to create a custom function for handling queries. Just include this function in every script. And use db_query(in this example) instead of mysql_query.
This example prompts an error in debugmode (variable $b_debugmode ). An e-mail with the error will be sent to the site operator otherwise.
The script writes a log file in directory ( in this case /log ) as well.
The system is vulnerable when database/query information is prompted to visitors. So be sure to hide this information for visitors anytime.
Regars,
Lennart Poot
http://www.twing.nl
<?php
$b_debugmode = 1; // 0 || 1$system_operator_mail = 'developer@company.com';
$system_from_mail = 'info@mywebsite.com';
function
db_query( $query ){
global $b_debugmode;// Perform Query
$result = mysql_query($query);// Check result
// This shows the actual query sent to MySQL, and the error. Useful for debugging.
if (!$result) {
if($b_debugmode){
$message = '<b>Invalid query:</b><br>' . mysql_error() . '<br><br>';
$message .= '<b>Whole query:</b><br>' . $query . '<br><br>';
die($message);
}raise_error('db_query_error: ' . $message);
}
return $result;
}
function
raise_error( $message ){
global $system_operator_mail, $system_from_mail;$serror=
"Env: " . $_SERVER['SERVER_NAME'] . "\r\n" .
"timestamp: " . Date('m/d/Y H:i:s') . "\r\n" .
"script: " . $_SERVER['PHP_SELF'] . "\r\n" .
"error: " . $message ."\r\n\r\n";// open a log file and write error
$fhandle = fopen( '/logs/errors'.date('Ymd').'.txt', 'a' );
if($fhandle){
fwrite( $fhandle, $serror );
fclose(( $fhandle ));
}// e-mail error to system operator
if(!$b_debugmode)
mail($system_operator_mail, 'error: '.$message, $serror, 'From: ' . $system_from_mail );
}?>
Anonymous ¶
22 years ago
some error can't handle. Example:
ERROR 1044: Access denied for user: 'ituser@mail.ramon.intranet' to database 'itcom'
This error ocurrs when a intent of a sql insert of no authorized user. The results: mysql_errno = 0 and the mysql_error = "" .
Anonymous ¶
18 years ago
My suggested implementation of mysql_error():
$result = mysql_query($query) or die("<b>A fatal MySQL error occured</b>.\n<br />Query: " . $query . "<br />\nError: (" . mysql_errno() . ") " . mysql_error());
This will print out something like...
A fatal MySQL error occured.
Query: SELECT * FROM table
Error: (err_no) Bla bla bla, you did everything wrong
It's very useful to see your query in order to detect problems with syntax. Most often, the output message from MySQL doesn't let you see enough of the query in the error message to let you see where your query went bad- it a missing quote, comma, or ( or ) could have occured well before the error was detected. I do -not- recomend using this procedure, however, for queries which execute on your site that are not user-specific as it has the potential to leak sensative data. Recomended use is just for debugging/building a script, and for general user-specific queries which would at the worst, leak the users own information to themself.
Good luck,
-Scott
olaf at amen-online dot de ¶
19 years ago
When dealing with user input, make sure that you use
<?php
echo htmlspecialchars (mysql_error ());
?>
instead of
<?php
echo mysql_error ();
?>
Otherwise it might be possible to crack into your system by submitting data that causes the SQL query to fail and that also contains javascript commands.
Would it make sense to change the examples in the documentation for mysql_query () and for mysql_error () accordingly?
josh ><> ¶
19 years ago
Oops, the code in my previous post only works for queries that don't return data (INSERT, UPDATE, DELETE, etc.), this updated function should work for all types of queries (using $result = myquery($query);):
function myquery ($query) {
$result = mysql_query($query);
if (mysql_errno())
echo "MySQL error ".mysql_errno().": ".mysql_error()."\n<br>When executing:<br>\n$query\n<br>";
return $result;
}
Gianluigi_Zanettini-MegaLab.it ¶
16 years ago
A friend of mine proposed a great solution.
<?php
$old_track = ini_set('track_errors', '1');
.....
if (
$this->db_handle!=FALSE && $db_selection_status!=FALSE)
{
$this->connected=1;
ini_set('track_errors', $old_track);
}
else
{
$this->connected=-1;
$mysql_warning=$php_errormsg;
ini_set('track_errors', $old_track);
throw new mysql_cns_exception(1, $mysql_warning . " " . mysql_error());
}
?>
scott at rocketpack dot net ¶
20 years ago
My suggested implementation of mysql_error():
$result = mysql_query($query) or die("<b>A fatal MySQL error occured</b>.\n<br />Query: " . $query . "<br />\nError: (" . mysql_errno() . ") " . mysql_error());
This will print out something like...
<b>A fatal MySQL error occured</b>.
Query: SELECT * FROM table
Error: (err_no) Bla bla bla, you did everything wrong
It's very useful to see your query in order to detect problems with syntax. Most often, the output message from MySQL doesn't let you see enough of the query in the error message to let you see where your query went bad- it a missing quote, comma, or ( or ) could have occured well before the error was detected. I do -not- recomend using this procedure, however, for queries which execute on your site that are not user-specific as it has the potential to leak sensative data. Recomended use is just for debugging/building a script, and for general user-specific queries which would at the worst, leak the users own information to themself.
Good luck,
-Scott
Gianluigi_Zanettini-MegaLab.it ¶
16 years ago
"Errors coming back from the MySQL database backend no longer issue warnings." Please note, you have an error/bug here. In fact, MySQL 5.1 with PHP 5.2:
Warning: mysql_connect() [function.mysql-connect]: Unknown MySQL server host 'locallllllhost' (11001)
That's a warning, which is not trapped by mysql_error()!
phpnet at robzazueta dot com ¶
16 years ago
This is a big one - As of MySQL 4.1 and above, apparently, the way passwords are hashed has changed. PHP 4.x is not compatible with this change, though PHP 5.0 is. I'm still using the 4.x series for various compatibility reasons, so when I set up MySQL 5.0.x on IIS 6.0 running PHP 4.4.4 I was surpised to get this error from mysql_error():
MYSQL: Client does not support authentication protocol requested by server; consider upgrading MySQL client
According to the MySQL site (http://dev.mysql.com/doc/refman/5.0/en/old-client.html) the best fix for this is to use the OLD_PASSWORD() function for your mysql DB user. You can reset it by issuing to MySQL:
Set PASSWORD for 'user'@'host' = OLD_PASSWORD('password');
This saved my hide.
miko_il AT yahoo DOT com ¶
19 years ago
Gerrit ¶
9 years ago
The following code returns two times the same error, even though I would have expected only one:
$ conn = mysql_connect ('localhost', 'root', '');
$ conn2 = mysql_connect ('localhost', 'root', '');
mysql_select_db ('db1', $ conn);
mysql_select_db ('db2', $ conn2);
$ result = mysql_query ("select 1 from dual", $ conn);
$ result2 = mysql_query ("select 1 from luad", $ conn2);
echo mysql_error ($ conn) "<hr>".
echo mysql_error ($ conn2) "<hr>".
The reason for this is that mysql_connect not working as expected a further connection returns. Since the parameters are equal, a further reference to the previous link is returned. So also changes the second mysql_select_db the selected DB of $conn to 'db2'.
If you change the connection parameters of the second connection to 127.0.0.1, a new connection is returned. In addition to the parameters new_link the mysql_connect() function to be forced.
mysqli_error
(PHP 5, PHP 7, PHP 
mysqli::$error — mysqli_error — Возвращает строку с описанием последней ошибки
Описание
Объектно-ориентированный стиль
Процедурный стиль
mysqli_error(mysqli $mysql): string
Возвращаемые значения
Строка с описанием ошибки. Пустая строка, если ошибки нет.
Примеры
Пример #1 Пример с $mysqli->error
Объектно-ориентированный стиль
<?php
$mysqli = new mysqli("localhost", "my_user", "my_password", "world");/* Проверить соединение */
if ($mysqli->connect_errno) {
printf("Соединение не удалось: %s\n", $mysqli->connect_error);
exit();
}
if (!
$mysqli->query("SET a=1")) {
printf("Сообщение ошибки: %s\n", $mysqli->error);
}/* Закрыть соединение */
$mysqli->close();
?>
Процедурный стиль
<?php
$link = mysqli_connect("localhost", "my_user", "my_password", "world");/* Проверить соединение */
if (mysqli_connect_errno()) {
printf("Соединение не удалось: %s\n", mysqli_connect_error());
exit();
}
if (!
mysqli_query($link, "SET a=1")) {
printf("Сообщение ошибки: %s\n", mysqli_error($link));
}/* Закрыть соединение */
mysqli_close($link);
?>
Результат выполнения данных примеров:
Сообщение ошибки: Unknown system variable 'a'
Смотрите также
- mysqli_connect_errno() — Возвращает код ошибки последней попытки соединения
- mysqli_connect_error() — Возвращает описание последней ошибки подключения
- mysqli_errno() — Возвращает код ошибки последнего вызова функции
- mysqli_sqlstate() — Возвращает код состояния SQLSTATE последней MySQL операции
information at saunderswebsolutions dot com ¶
17 years ago
The mysqli_sql_exception class is not available to PHP 5.05
I used this code to catch errors
<?php
$query = "SELECT XXname FROM customer_table ";
$res = $mysqli->query($query);
if (!
$res) {
printf("Errormessage: %s\n", $mysqli->error);
}?>
The problem with this is that valid values for $res are: a mysqli_result object , true or false
This doesn't tell us that there has been an error with the sql used.
If you pass an update statement, false is a valid result if the update fails.
So, a better way is:
<?php
$query = "SELECT XXname FROM customer_table ";
$res = $mysqli->query($query);
if (!
$mysqli->error) {
printf("Errormessage: %s\n", $mysqli->error);
}?>
This would output something like:
Unexpected PHP error [mysqli::query() [<a href='function.query'>function.query</a>]: (42S22/1054): Unknown column 'XXname' in 'field list'] severity [E_WARNING] in [G:\database.php] line [249]
Very frustrating as I wanted to also catch the sql error and print out the stack trace.
A better way is:
<?php
mysqli_report(MYSQLI_REPORT_OFF); //Turn off irritating default messages$mysqli = new mysqli("localhost", "my_user", "my_password", "world");$query = "SELECT XXname FROM customer_table ";
$res = $mysqli->query($query);
if (
$mysqli->error) {
try {
throw new Exception("MySQL error $mysqli->error <br> Query:<br> $query", $msqli->errno);
} catch(Exception $e ) {
echo "Error No: ".$e->getCode(). " - ". $e->getMessage() . "<br >";
echo nl2br($e->getTraceAsString());
}
}//Do stuff with the result
?>
Prints out something like:
Error No: 1054
Unknown column 'XXname' in 'field list'
Query:
SELECT XXname FROM customer_table
#0 G:\\database.php(251): database->dbError('Unknown column ...', 1054, 'getQuery()', 'SELECT XXname F...')
#1 G:\data\WorkSites\1framework5\tests\dbtest.php(29): database->getString('SELECT XXname F...')
#2 c:\PHP\includes\simpletest\runner.php(58): testOfDB->testGetVal()
#3 c:\PHP\includes\simpletest\runner.php(96): SimpleInvoker->invoke('testGetVal')
#4 c:\PHP\includes\simpletest\runner.php(125): SimpleInvokerDecorator->invoke('testGetVal')
#5 c:\PHP\includes\simpletest\runner.php(183): SimpleErrorTrappingInvoker->invoke('testGetVal')
#6 c:\PHP\includes\simpletest\simple_test.php(90): SimpleRunner->run()
#7 c:\PHP\includes\simpletest\simple_test.php(498): SimpleTestCase->run(Object(HtmlReporter))
#8 c:\PHP\includes\simpletest\simple_test.php(500): GroupTest->run(Object(HtmlReporter))
#9 G:\all_tests.php(16): GroupTest->run(Object(HtmlReporter))
This will actually print out the error, a stack trace and the offending sql statement. Much more helpful when the sql statement is generated somewhere else in the code.
se (at) brainbits (dot) net ¶
17 years ago
The decription "mysqli_error -- Returns a string description of the LAST error" is not exactly that what you get from mysqli_error. You get the error description from the last mysqli-function, not from the last mysql-error.
If you have the following situation
if (!$mysqli->query("SET a=1")) {
$mysqli->query("ROLLBACK;")
printf("Errormessage: %s\n", $mysqli->error);
}
you don't get an error-message, if the ROLLBACK-Query didn't failed, too. In order to get the right error-message you have to write:
if (!$mysqli->query("SET a=1")) {
printf("Errormessage: %s\n", $mysqli->error);
$mysqli->query("ROLLBACK;")
}
callforeach at gmail dot com ¶
8 years ago
I had to set mysqli_report(MYSQLI_REPORT_ALL) at the begin of my script to be able to catch mysqli errors within the catch block of my php code.
Initially, I used the below code to throw and subsequent catch mysqli exceptions
<?php
try {
$mysqli = new mysqli('localhost','root','pwd','db');
if ($mysqli->connect_errno)
throw new Exception($mysqli->connect_error);
} catch (
Exception $e) {
echo $e->getMessage();
}I realized the exception was being thrown before the actual throw statement and hence the catch block was not being called.My current code looks like
mysqli_report(MYSQLI_REPORT_ALL) ;
try {
$mysqli = new mysqli('localhost','root','pwd','db');
/* I don't need to throw the exception, it's being thrown automatically */} catch (Exception $e) {
echo $e->getMessage();
}This works fine and I'm able to trap all mysqli errors
asmith16 at littlesvr dot ca ¶
9 years ago
Please note that the string returned may contain data initially provided by the user, possibly making your code vulnerable to XSS.
So even if you escape everything in your SQL query using mysqli_real_escape_string(), make sure that if you plan to display the string returned by mysqli_error() you run that string through htmlspecialchars().
As far as I can tell the two escape functions don't escape the same characters, which is why you need both (the first for SQL and the second for HTML/JS).
abderrahmanekaddour dot aissat at gmail dot com ¶
1 year ago
<?php// The idea is the add formated errors information for developers to easier bugs detection.$myfile = fopen("database_log.log", "r");
$db = new mysqli("localhost", "root","root","data");
if(!$db->query("SELECT")){
$timestamp = new DateTime();
$data_err = " {
\"title\": \" Select statement error \",
\"date_time\": ".$timestamp->getTimestamp().",
\"error\":\" ".$db->error." \"
} "; // Do more information
fwrite($myfile, $data_err); // writing data
}
// In separate file do file read and format it for good visual.$db->close();
fclose($myfile);
?>
information at saunderswebsolutions dot com ¶
17 years ago
Hi, you can also use the new mysqli_sql_exception to catch sql errors.
Example:
<?php
//set up $mysqli_instance here..
$Select = "SELECT xyz FROM mytable ";
try {
$res = $mysqli_instance->query($Select);
}catch (mysqli_sql_exception $e) {
print "Error Code <br>".$e->getCode();
print "Error Message <br>".$e->getMessage();
print "Strack Trace <br>".nl2br($e->getTraceAsString());
}?>
Will print out something like
Error Code: 0
Error Message
No index used in query/prepared statement select sess_value from frame_sessions where sess_name = '5b85upjqkitjsostvs6g9rkul1'
Strack Trace:
#0 G:\classfiles\lib5\database.php(214): mysqli->query('select sess_val...')
#1 G:\classfiles\lib5\Session.php(52): database->getString('select sess_val...')
#2 [internal function]: sess_read('5b85upjqkitjsos...')
#3 G:\classfiles\includes.php(50): session_start()
#4 G:\tests\all_tests.php(4): include('G:\data\WorkSit...')
#5 {main}
Anonymous ¶
3 years ago
mysqli_report(MYSQLI_REPORT_ERROR | MYSQLI_REPORT_STRICT);
try {
$this->connection = mysqli_connect($hostname,$username,$password, $dbname);
} catch (Exception $e) {
echo "Errno: " . mysqli_connect_errno() . PHP_EOL;
echo "Text error: " . mysqli_connect_error() . PHP_EOL;
exit;
}
Правильная обработка ошибок позволяет сделать стабильное приложение, которое не будет завершаться неожиданно. В случае возникновения непредвиденной ситуации программа должна выдавать вменяемый ответ, почему она не хочет исполнится. И создание правильного механизма обработки ошибок — это задача программиста.
В этой статье рассмотрим два вида ошибок, которые могут возникнуть при программировании взаимодействия с базой данных. Первый тип — это ошибка подключения к базе данных. Второй тип — это ошибка выполнения запроса к базе данных. Для обработки этих ошибок будем использовать специальные функции для работы с базой.
Ошибка соединения с базой данных
Сразу приведём пример обработки ошибки с соединением с базой данных:
<?php
$host = 'localhost'; // адрес сервера
$db_name = 'database'; // имя базы данных
$user = 'user'; // имя пользователя
$password = 'password'; // пароль
// создание подключения к базе
$connection = mysqli_connect($host, $user, $password, $db_name);
// проверка правильности подключения
if(!$connection){ // при соединении с базой данных возникла ошибка
echo 'Ошибка соединения: ' . mysqli_connect_error() . '<br>';
echo 'Код ошибки: ' . mysqli_connect_errno();
}else{ // соединение было установлено успешно
// здесь можно делать запрос к базе,
// потому что соединение успешно установлено
}
?>
В этом примере можно заметить функцию mysqli_connect_error. Она выводит текстовое описание ошибки подключения (на английском языке). В отличии от неё функция mysqli_connect_errno выводит числовой код ошибки, к примеру «1045».
Ошибка запроса к базе
Теперь попробуем доработать пример из предыдущего параграфа и добавить запрос к базе данных. Не будем вдаваться в детали, что будет записано в тексте SQL запроса, просто предположим, что он может завершиться ошибкой. К примеру, из-за неожиданного отключения сервера с базой данных от сети. В примере добавим проверку на наличие ошибок при выполнении запроса:
<?php
$host = 'localhost'; // адрес сервера
$db_name = 'database'; // имя базы данных
$user = 'user'; // имя пользователя
$password = 'password'; // пароль
// создание подключения к базе
$connection = mysqli_connect($host, $user, $password, $db_name);
if(!$connection){ // проверка правильности подключения
echo 'Ошибка соединения: ' . mysqli_connect_error() . '<br>';
echo 'Код ошибки: ' . mysqli_connect_errno();
}else{ // подключение успешно установлено
// текст SQL запроса, который будет передан базе
$query = 'SELECT * FROM `USERS`';
// выполняем запрос к базе данных
$result = mysqli_query($connection, $query);
if(!$result){ // запрос завершился ошибкой
echo 'Ошибка запроса: ' . mysqli_error($connection) . '<br>';
echo 'Код ошибки: ' . mysqli_errno($connection);
}else{ // запрос успешно выполнился
while($row = $result->fetch_assoc()){
// обрабатываем полученные данные
}
}
// закрываем соединение с базой
mysqli_close($connection);
}
?>
В этом примере есть две функции, которые работают с ошибками базы. Функция mysqli_error возвращает описание ошибки запроса (на английском языке), а функция mysqli_errno возвращает числовой код ошибки, к примеру, «1193».
Обратите внимание, что все функции обработки ошибок в этой статье (mysqli_connect_error, mysqli_connect_errno, mysqli_error, mysqli_errno) возвращают информацию только о последней ошибке. Но ошибок может быть несколько.
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mysqli::$error
mysqli_error
(PHP 5, PHP 7)
mysqli::$error — mysqli_error — Возвращает строку с описанием последней ошибки
Описание
Объектно-ориентированный стиль
Процедурный стиль
string mysqli_error
( mysqli $link
)
Возвращаемые значения
Строка с описанием ошибки. Пустая строка, если ошибки нет.
Примеры
Пример #1 Пример с $mysqli->error
Объектно-ориентированный стиль
<?php
$mysqli = new mysqli("localhost", "my_user", "my_password", "world");/* check connection */
if ($mysqli->connect_errno) {
printf("Connect failed: %s\n", $mysqli->connect_error);
exit();
}
if (!
$mysqli->query("SET a=1")) {
printf("Errormessage: %s\n", $mysqli->error);
}/* close connection */
$mysqli->close();
?>
Процедурный стиль
<?php
$link = mysqli_connect("localhost", "my_user", "my_password", "world");/* check connection */
if (mysqli_connect_errno()) {
printf("Connect failed: %s\n", mysqli_connect_error());
exit();
}
if (!
mysqli_query($link, "SET a=1")) {
printf("Errormessage: %s\n", mysqli_error($link));
}/* close connection */
mysqli_close($link);
?>
Результат выполнения данных примеров:
Errormessage: Unknown system variable 'a'
Смотрите также
- mysqli_connect_errno() — Возвращает код ошибки последней попытки соединения
- mysqli_connect_error() — Возвращает описание последней ошибки подключения
- mysqli_errno() — Возвращает код ошибки последнего вызова функции
- mysqli_sqlstate() — Возвращает код состояния SQLSTATE последней MySQL операции
Вернуться к: mysqli
I’m using PHP and PDO to connect to my MySQL database. I configured the PDO connection so that I get any MySQL error thrown as an exception:
$dbConnection->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);
Now lets suppose I execute a MySQL command that generates an error and I catch it, the error message is this:
SQLSTATE[23000]: Integrity constraint violation: 1048 Column ‘Name’ cannot be null
When I use $exception->getCode() it returns 23000, which I think is from PHP or something. How do I get the specific MySQL error (1048) inside a catch block?
Danny Beckett
20.5k24 gold badges107 silver badges134 bronze badges
asked Apr 12, 2013 at 0:59
1
A PDOException object has a property errorInfo which is a three-element array, the same returned by PDO::errorInfo(). The MySQL error code is element 1.
try {
. . .
} catch (PDOException $e)
$errorInfo = $e->errorInfo;
error_log "MySQL error " . $errorInfo[1] . "\n";
}
PS: Note that just echoing the error is not proper exception handling, I’m just doing that to show how to access the info.
answered Apr 12, 2013 at 1:07
Bill KarwinBill Karwin
539k86 gold badges674 silver badges830 bronze badges
Since you’re using PDO, you can refer to here, which provide an excellent description and example on how to get the error info from SQL.
answered Apr 12, 2013 at 1:06
viclimviclim
9598 silver badges16 bronze badges
