Получить ошибку mysql php

(PHP 4, PHP 5)

mysql_errorВозвращает текст ошибки последней операции с MySQL

Описание

mysql_error(resource $link_identifier = NULL): string

Список параметров

link_identifier

Соединение MySQL. Если идентификатор соединения не был указан,
используется последнее соединение, открытое mysql_connect(). Если такое соединение не было найдено,
функция попытается создать таковое, как если бы mysql_connect() была вызвана без параметров.
Если соединение не было найдено и не смогло быть создано, генерируется ошибка уровня E_WARNING.

Возвращаемые значения

Возвращает текст ошибки выполнения последней функции MySQL,
или '' (пустую строку), если операция
выполнена успешно.

Примеры

Пример #1 Пример использования mysql_error()

<?php
$link
= mysql_connect("localhost", "mysql_user", "mysql_password");mysql_select_db("nonexistentdb", $link);
echo
mysql_errno($link) . ": " . mysql_error($link). "\n";mysql_select_db("kossu", $link);
mysql_query("SELECT * FROM nonexistenttable", $link);
echo
mysql_errno($link) . ": " . mysql_error($link) . "\n";
?>

Результатом выполнения данного примера
будет что-то подобное:

1049: Unknown database 'nonexistentdb'
1146: Table 'kossu.nonexistenttable' doesn't exist

aleczapka _at) gmx dot net

19 years ago

If you want to display errors like "Access denied...", when mysql_error() returns "" and mysql_errno() returns 0, use $php_errormsg. This Warning will be stored there. You need to have track_errors set to true in your php.ini.

Note. There is a bug in either documentation about error_reporting() or in mysql_error() function cause manual for mysql_error(), says: "Errors coming back from the MySQL database backend no longer issue warnings." Which is not true.

Pendragon Castle

14 years ago

Using a manipulation of josh ><>'s function, I created the following. It's purpose is to use the DB to store errors. It handles both original query, as well as the error log. Included Larry Ullman's escape_data() as well since I use it in q().

<?php

function escape_data($data){

global
$dbc;

if(
ini_get('magic_quotes_gpc')){

$data=stripslashes($data);

}

return
mysql_real_escape_string(trim($data),$dbc);

}

function

q($page,$query){

// $page

$result = mysql_query($query);

if (
mysql_errno()) {

$error = "MySQL error ".mysql_errno().": ".mysql_error()."\n<br>When executing:<br>\n$query\n<br>";

$log = mysql_query("INSERT INTO db_errors (error_page,error_text) VALUES ('$page','".escape_data($error)."')");

}

}
// Run the query using q()

$query = "INSERT INTO names (first, last) VALUES ('myfirst', 'mylast'");

$result = q("Sample Page Title",$query);

?>

Florian Sidler

13 years ago

Be aware that if you are using multiple MySQL connections you MUST support the link identifier to the mysql_error() function. Otherwise your error message will be blank.

Just spent a good 30 minutes trying to figure out why i didn't see my SQL errors.

l dot poot at twing dot nl

17 years ago

When creating large applications it's quite handy to create a custom function for handling queries. Just include this function in every script. And use db_query(in this example) instead of mysql_query.

This example prompts an error in debugmode (variable $b_debugmode ). An e-mail with the error will be sent to the site operator otherwise.

The script writes a log file in directory ( in this case /log ) as well.

The system is vulnerable when database/query information is prompted to visitors. So be sure to hide this information for visitors anytime.

Regars,

Lennart Poot
http://www.twing.nl

<?php
$b_debugmode
= 1; // 0 || 1$system_operator_mail = 'developer@company.com';
$system_from_mail = 'info@mywebsite.com';

function

db_query( $query ){
global
$b_debugmode;// Perform Query
$result = mysql_query($query);// Check result
// This shows the actual query sent to MySQL, and the error. Useful for debugging.
if (!$result) {
if(
$b_debugmode){
$message = '<b>Invalid query:</b><br>' . mysql_error() . '<br><br>';
$message .= '<b>Whole query:</b><br>' . $query . '<br><br>';
die(
$message);
}
raise_error('db_query_error: ' . $message);
}
return
$result;
}

function

raise_error( $message ){
global
$system_operator_mail, $system_from_mail;$serror=
"Env: " . $_SERVER['SERVER_NAME'] . "\r\n" .
"timestamp: " . Date('m/d/Y H:i:s') . "\r\n" .
"script: " . $_SERVER['PHP_SELF'] . "\r\n" .
"error: " . $message ."\r\n\r\n";// open a log file and write error
$fhandle = fopen( '/logs/errors'.date('Ymd').'.txt', 'a' );
if(
$fhandle){
fwrite( $fhandle, $serror );
fclose(( $fhandle ));
}
// e-mail error to system operator
if(!$b_debugmode)
mail($system_operator_mail, 'error: '.$message, $serror, 'From: ' . $system_from_mail );
}
?>

Anonymous

22 years ago

some error can't handle. Example:

ERROR 1044: Access denied for user: 'ituser@mail.ramon.intranet' to database 'itcom'

This error ocurrs when a intent of a sql insert of no authorized user. The results: mysql_errno = 0 and the mysql_error = "" .

Anonymous

18 years ago

My suggested implementation of mysql_error():

$result = mysql_query($query) or die("<b>A fatal MySQL error occured</b>.\n<br />Query: " . $query . "<br />\nError: (" . mysql_errno() . ") " . mysql_error());

This will print out something like...

A fatal MySQL error occured.

Query: SELECT * FROM table

Error: (err_no) Bla bla bla, you did everything wrong

It's very useful to see your query in order to detect problems with syntax. Most often, the output message from MySQL doesn't let you see enough of the query in the error message to let you see where your query went bad- it a missing quote, comma, or ( or ) could have occured well before the error was detected. I do -not- recomend using this procedure, however, for queries which execute on your site that are not user-specific as it has the potential to leak sensative data. Recomended use is just for debugging/building a script, and for general user-specific queries which would at the worst, leak the users own information to themself.

Good luck,

-Scott

olaf at amen-online dot de

19 years ago

When dealing with user input, make sure that you use
<?php
echo htmlspecialchars (mysql_error ());
?>
instead of
<?php
echo mysql_error ();
?>

Otherwise it might be possible to crack into your system by submitting data that causes the SQL query to fail and that also contains javascript commands.

Would it make sense to change the examples in the documentation for mysql_query () and for mysql_error () accordingly?

josh ><>

19 years ago

Oops, the code in my previous post only works for queries that don't return data (INSERT, UPDATE, DELETE, etc.), this updated function should work for all types of queries (using $result = myquery($query);):

function myquery ($query) {
$result = mysql_query($query);
if (mysql_errno())
echo "MySQL error ".mysql_errno().": ".mysql_error()."\n<br>When executing:<br>\n$query\n<br>";
return $result;
}

Gianluigi_Zanettini-MegaLab.it

16 years ago

A friend of mine proposed a great solution.

<?php
$old_track
= ini_set('track_errors', '1');

.....

if (

$this->db_handle!=FALSE && $db_selection_status!=FALSE)
{
$this->connected=1;
ini_set('track_errors', $old_track);
}
else
{
$this->connected=-1;
$mysql_warning=$php_errormsg;
ini_set('track_errors', $old_track);
throw new
mysql_cns_exception(1, $mysql_warning . " " . mysql_error());
}
?>

scott at rocketpack dot net

20 years ago

My suggested implementation of mysql_error():

$result = mysql_query($query) or die("<b>A fatal MySQL error occured</b>.\n<br />Query: " . $query . "<br />\nError: (" . mysql_errno() . ") " . mysql_error());

This will print out something like...

<b>A fatal MySQL error occured</b>.
Query: SELECT * FROM table
Error: (err_no) Bla bla bla, you did everything wrong

It's very useful to see your query in order to detect problems with syntax. Most often, the output message from MySQL doesn't let you see enough of the query in the error message to let you see where your query went bad- it a missing quote, comma, or ( or ) could have occured well before the error was detected. I do -not- recomend using this procedure, however, for queries which execute on your site that are not user-specific as it has the potential to leak sensative data. Recomended use is just for debugging/building a script, and for general user-specific queries which would at the worst, leak the users own information to themself.

Good luck,

-Scott

Gianluigi_Zanettini-MegaLab.it

16 years ago

"Errors coming back from the MySQL database backend no longer issue warnings." Please note, you have an error/bug here. In fact, MySQL 5.1 with PHP 5.2:

Warning: mysql_connect() [function.mysql-connect]: Unknown MySQL server host 'locallllllhost' (11001)

That's a warning, which is not trapped by mysql_error()!

phpnet at robzazueta dot com

16 years ago

This is a big one - As of MySQL 4.1 and above, apparently, the way passwords are hashed has changed. PHP 4.x is not compatible with this change, though PHP 5.0 is. I'm still using the 4.x series for various compatibility reasons, so when I set up MySQL 5.0.x on IIS 6.0 running PHP 4.4.4 I was surpised to get this error from mysql_error():

MYSQL: Client does not support authentication protocol requested by server; consider upgrading MySQL client

According to the MySQL site (http://dev.mysql.com/doc/refman/5.0/en/old-client.html) the best fix for this is to use the OLD_PASSWORD() function for your mysql DB user. You can reset it by issuing to MySQL:

Set PASSWORD for 'user'@'host' = OLD_PASSWORD('password');

This saved my hide.

miko_il AT yahoo DOT com

19 years ago

Gerrit

9 years ago

The following code returns two times the same error, even though I would have expected only one:

$ conn = mysql_connect ('localhost', 'root', '');
$ conn2 = mysql_connect ('localhost', 'root', '');

mysql_select_db ('db1', $ conn);
mysql_select_db ('db2', $ conn2);

$ result = mysql_query ("select 1 from dual", $ conn);
$ result2 = mysql_query ("select 1 from luad", $ conn2);

echo mysql_error ($ conn) "<hr>".
echo mysql_error ($ conn2) "<hr>".

The reason for this is that mysql_connect not working as expected a further connection returns. Since the parameters are equal, a further reference to the previous link is returned. So also changes the second mysql_select_db the selected DB of $conn to 'db2'.

If you change the connection parameters of the second connection to 127.0.0.1, a new connection is returned. In addition to the parameters new_link the mysql_connect() function to be forced.

За последние 24 часа нас посетили 17390 программистов и 1376 роботов. Сейчас ищут 454 программиста …

mysqli::$error

mysqli_error

(PHP 5, PHP 7)

mysqli::$errormysqli_errorВозвращает строку с описанием последней ошибки

Описание

Объектно-ориентированный стиль

Процедурный стиль

string mysqli_error
( mysqli $link
)

Возвращаемые значения

Строка с описанием ошибки. Пустая строка, если ошибки нет.

Примеры

Пример #1 Пример с $mysqli->error

Объектно-ориентированный стиль


<?php
$mysqli 
= new mysqli("localhost""my_user""my_password""world");/* check connection */
if ($mysqli->connect_errno) {
    
printf("Connect failed: %s\n"$mysqli->connect_error);
    exit();
}

if (!

$mysqli->query("SET a=1")) {
    
printf("Errormessage: %s\n"$mysqli->error);
}
/* close connection */
$mysqli->close();
?>

Процедурный стиль


<?php
$link 
mysqli_connect("localhost""my_user""my_password""world");/* check connection */
if (mysqli_connect_errno()) {
    
printf("Connect failed: %s\n"mysqli_connect_error());
    exit();
}

if (!

mysqli_query($link"SET a=1")) {
    
printf("Errormessage: %s\n"mysqli_error($link));
}
/* close connection */
mysqli_close($link);
?>

Результат выполнения данных примеров:

Errormessage: Unknown system variable 'a'

Смотрите также

  • mysqli_connect_errno() — Возвращает код ошибки последней попытки соединения
  • mysqli_connect_error() — Возвращает описание последней ошибки подключения
  • mysqli_errno() — Возвращает код ошибки последнего вызова функции
  • mysqli_sqlstate() — Возвращает код состояния SQLSTATE последней MySQL операции

Вернуться к: mysqli

I have a mysqli query that wont execute and I would like to display information about why that’s happening. Im just fooling around with this example but I imagine something like this:

$myQuery= $mysqli->query("UPDATE table SET id = 1 WHERE id = 3");
if(!$myQuery) //If query couldnt be executed
{
echo $mysqli->error; //Display information about why wasnt executed (eg. Error: couldnt find table)
}

asked Apr 10, 2017 at 4:49

nightlynutria's user avatar

1

try using

// Perform a query, check for error
if (!mysqli_query($con,"UPDATE table SET id = 1 WHERE id = 3"))
{
 echo("Error description: " . mysqli_error($con));
}

mysqli_close($con);

answered Apr 10, 2017 at 4:53

Nishant Nair's user avatar

Nishant NairNishant Nair

1,9991 gold badge13 silver badges18 bronze badges

0

mysqli::$error

mysqli_error

(PHP 5, PHP 7, PHP 8)

mysqli::$error —mysqli_error-Возвращает строковое описание последней ошибки

Description

Object-oriented style

Procedural style

mysqli_error(mysqli $mysql): string

Возвращает последнее сообщение об ошибке при последнем вызове функции MySQLi,который может увенчаться успехом или неудачей.

Return Values

Строка,описывающая ошибку.Пустая строка,если ошибка не произошла.

Examples

Пример # 1 $mysqli->error Пример

Object-oriented style

<?php
$mysqli new mysqli("localhost""my_user""my_password""world");


if ($mysqli->connect_errno) {
    printf("Connect failed: %s\n"$mysqli->connect_error);
    exit();
}

if (!$mysqli->query("SET a=1")) {
    printf("Error message: %s\n"$mysqli->error);
}


$mysqli->close();
?>

Procedural style

<?php
$link = mysqli_connect("localhost""my_user""my_password""world");


if (mysqli_connect_errno()) {
    printf("Connect failed: %s\n", mysqli_connect_error());
    exit();
}

if (!mysqli_query($link"SET a=1")) {
    printf("Error message: %s\n", mysqli_error($link));
}


mysqli_close($link);
?>

Приведенные выше примеры будут выведены на экран:

Error message: Unknown system variable 'a'

See Also

  • mysqli_connect_errno () — возвращает код ошибки из последнего вызова соединения
  • mysqli_connect_error () — Возвращает описание последней ошибки подключения
  • mysqli_errno () — возвращает код ошибки для последнего вызова функции
  • mysqli_sqlstate () — возвращает ошибку SQLSTATE из предыдущей операции MySQL

mysqli_error() function / mysqli::$error

The mysqli_error() function / mysqli::$error returns the last error description for the most recent function call, if any.

Syntax:

Object oriented style

string $mysqli->error;

Procedural style

string mysqli_error ( mysqli $link )

Parameter:

Name Description Required/Optional
link A link identifier returned by mysqli_connect() or mysqli_init() Required for procedural style only and Optional for Object oriented style

Usage: Procedural style

mysqli_error(connection);

Parameter:

Name Description Required/Optional
connection Specifies the MySQL connection to use. Required

Return value:

A string that describes the error. An empty string if no error occurred.

Version: PHP 5, PHP 7

Example of object oriented style:

<?php
$mysqli = new mysqli("localhost", "user1", "datasoft123", "hr");

/* check connection */
if ($mysqli->connect_errno) {
    printf("Connect failed: %s\n", $mysqli->connect_error);
    exit();
}

if (!$mysqli->query("SET a=1")) {
    printf("Errormessage: %s\n", $mysqli->error);
}

/* close connection */
$mysqli->close();
?>

Output:

Errormessage: Unknown system variable 'a'

Example of procedural style:

<?php

$link = mysqli_connect("localhost", "my_user", "my_password", "world");

/* check connection */
if (mysqli_connect_errno()) {
    printf("Connect failed: %s\n", mysqli_connect_error());
    exit();
}

if (!mysqli_query($link, "SET a=1")) {
    printf("Errormessage: %s\n", mysqli_error($link));
}

/* close connection */
mysqli_close($link);
?>

Output:

Errormessage: Unknown system variable 'a'

Example:

<?php
$con=mysqli_connect("localhost","user1","datasoft123","hr");
// Check connection
if (mysqli_connect_errno())
  {
  echo "Failed to connect to MySQL: " . mysqli_connect_error();
  }

// Perform a query, check for error
if (!mysqli_query($con,"INSERT INTO employees (First_Name) VALUES ('David')"))
  {
  echo("Errorcode: " . mysqli_errno($con));
  }

mysqli_close($con);
?>

Sample Output:

Errorcode: 1146

See also

PHP Function Reference

Previous: error_list
Next: field_count

PHP: Tips of the Day

PHP: Saving image from PHP URL

If you have allow_url_fopen set to true:

$url = 'http://example.com/image.php';
$img = '/my/folder/flower.gif';
file_put_contents($img, file_get_contents($url));

Else use cURL:

$ch = curl_init('http://example.com/image.php');
$fp = fopen('/my/folder/flower.gif', 'wb');
curl_setopt($ch, CURLOPT_FILE, $fp);
curl_setopt($ch, CURLOPT_HEADER, 0);
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fclose($fp);

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